Suppose an all good crown has mass m=3800 grams. Gold has a density of 19 grams/ cm^3. What is the volume of water displaced by a gold crown (in cm^3)?

Please help :)

since density = mass/volume,

volume = mass/density. So, you will displace

3800g / (19 g/cm^3) = 200 cm^3

To find the volume of water displaced by a gold crown, we can use the concept of density. Density is defined as mass divided by volume (D = m/V). In this case, the density of gold is given as 19 grams/cm^3.

We are given the mass of the gold crown as 3800 grams. Using the formula D = m/V, we can rearrange it to solve for volume (V):

V = m/D

Substituting the given values, we have:

V = 3800 g / 19 g/cm^3

V = 200 cm^3

Therefore, the volume of water displaced by the gold crown is 200 cm^3.

Please note that the volume of water displaced by an object is equal to its own volume, according to Archimedes' principle.