find the slope of any line perpendicualr to the line through points (3,3) and (2,8)
so i did:
y= (8-3)/(2-8)= (5)/(-6)
to find another line perpendicular do i have to take one set of the points and substitute them into y=mx+b?
The slope for the perpendcular line is the negative inverse, or m= 6/5
To find the slope of any line perpendicular to another line, you need to first find the slope of the original line. Given the points (3,3) and (2,8), you correctly calculated the slope using the formula:
m = (y2 - y1) / (x2 - x1)
Substituting the values into the formula, you get:
m = (8 - 3) / (2 - 3)
= 5 / -1
= -5
Now, to find the slope of a line perpendicular to this line, you need to take the negative reciprocal of the original slope. The negative reciprocal of -5 is 1/5. Therefore, the slope of any line perpendicular to the line passing through the points (3,3) and (2,8) is 1/5.