Two acid solutions are available to a chemist. One is 10% nitric acid solution, the other is 4% nitric acid solution. How much of each type of solution should be mixed together to form a 600 ml of a 6% nitric acid solution?
Ix x ml of 10%, then the rest (600-x) is 4%. So,
.10(x) + .04(600-x) = .06(600)
10
To solve this problem, we can use the concept of the concentration of a solution, which is the amount of solute (in this case, nitric acid) dissolved in a given amount of solution (in this case, 600 ml).
Let's assume that x ml of the 10% nitric acid solution should be mixed with (600 - x) ml of the 4% nitric acid solution to obtain a 600 ml mixture with a 6% nitric acid concentration.
Here's how we can set up the equation:
Amount of nitric acid in 10% solution + amount of nitric acid in 4% solution = amount of nitric acid in 6% solution
(0.10 * x ml) + (0.04 * (600 - x) ml) = (0.06 * 600 ml)
Now, let's solve for x:
0.10x + 0.04(600 - x) = 0.06 * 600
0.10x + 24 - 0.04x = 36
0.06x = 36 - 24
0.06x = 12
x = 12 / 0.06
x = 200 ml
Therefore, 200 ml of the 10% nitric acid solution should be mixed with (600 - 200) ml = 400 ml of the 4% nitric acid solution to obtain 600 ml of a 6% nitric acid solution.