I have 3 grams of CaCI2 and dissolve this into 0.5 L water. What is the concentration in g/dl (grams/deciliter)? I take 10 milliliters of this solution and add it to 990 milliliters of watet fo a total of 1000 milliliters. What is the concentration of this new dilution in terms of molarity? I Must convert the mass concentration to moles/L, then convert to dl terms to liters, then use the dilution formula.the final unoys should be in moles/liter
3g CaCl2/0.5 L = 6/L = 0.6g/dL
dilute 10 mL to 1000 mL; new concn is
0.6g/dL x (10/1000) = 6E-3g/dL
mols = 6E-3/111 = approx 5.41E-5 mols in 6E-3g CaCl2.
Then 5.41E-5 mol/dL = 5.41E-4 mol/L - 5.41M.
I've estimated here and there; you should go through the math yourself including the molar mass of CaCl2.
Thank you :)
To find the concentration in g/dl (grams/deciliter) of the CaCl2 solution, we first need to calculate the moles of CaCl2 in the solution and then convert it to grams per deciliter.
Step 1: Convert grams of CaCl2 to moles.
The molar mass of CaCl2 is: (1 x atomic mass of Ca) + (2 x atomic mass of Cl) = (1 x 40.08) + (2 x 35.45) = 111.02 g/mol.
Number of moles of CaCl2 = Mass of CaCl2 / Molar mass of CaCl2
Number of moles of CaCl2 = 3 g / 111.02 g/mol
Number of moles of CaCl2 ≈ 0.027 moles
Step 2: Convert moles to concentration in moles/Liter (Molarity).
Molarity = Moles of solute / Volume of solution in liters
Given that 0.5 L of water is used to dissolve the 3 grams of CaCl2, the volume of the solution is 0.5 L.
Molarity = 0.027 moles / 0.5 L
Molarity = 0.054 M (moles per liter)
Step 3: Convert concentration to grams/deciliter.
1 L = 10 dl (deciliters)
So, to convert to grams/deciliter, we can multiply the molarity by the molar mass of CaCl2 and divide by 10.
Concentration (g/dl) = (Molarity x Molar mass of CaCl2) / 10
Concentration (g/dl) = (0.054 mol/L x 111.02 g/mol) / 10
Concentration (g/dl) ≈ 0.0595 g/dl
Therefore, the concentration of the CaCl2 solution is approximately 0.0595 g/dl.
Now, let's proceed to the second part of the question.
Given that you take 10 milliliters of the CaCl2 solution and add it to 990 milliliters of water to make a total volume of 1000 milliliters, we will calculate the concentration of this new dilution in terms of molarity.
Step 1: Calculate the new volume of the diluted solution.
The total volume of the diluted solution is 1000 milliliters, so the new volume is 1000 mL.
Step 2: Calculate the moles of CaCl2 in the 10 mL used.
Moles of CaCl2 = Concentration in moles/L x Volume in liters
Since the given volume is 10 mL, we need to convert it to liters: 10 mL / 1000 mL/L = 0.01 L
Moles of CaCl2 = 0.054 M x 0.01 L
Moles of CaCl2 = 0.00054 moles
Step 3: Calculate the new concentration of the diluted solution.
Molarity of diluted solution = Moles of solute / Volume of solution in liters
Molarity of diluted solution = 0.00054 moles / 1 L (since the total volume is 1000 mL, which is 1 L)
Molarity of diluted solution = 0.00054 M (moles per liter)
So, the concentration of the diluted solution in terms of molarity is approximately 0.00054 M.
Please note that the final concentration of the diluted solution is in moles per liter (M) as requested.