To drain a round swimming pool that is 18.0 ft wide and 3.75 ft deep, a worker uses a pump that can move 7.58 gallons of water per minute. how many minutes will it take to drain the swimming pool?

Area swimming pool is pi*r^2 and that x h is the area of a cylinder. That gives you cubic feet. Let's call that 1000 cubic feet.

1 gallon = 0.134 cubic feet.
7.58 gallons/min x (0.134 ft^3/gallon) = about 0.8 ft^3/min
0.8 ft^3/min x ?min = 1000 ft^3
Solve for min

To find out how many minutes it will take to drain the swimming pool, we need to calculate the volume of water in the pool and then divide it by the rate at which the pump can move water.

First, we need to calculate the volume of the pool. The formula for the volume of a cylinder (which is applicable to a round swimming pool) is V = π * r^2 * h, where V is the volume, π is a mathematical constant approximately equal to 3.14159, r is the radius (half the width), and h is the height (or depth) of the pool.

Given:
Width of the pool (diameter) = 18.0 ft
Radius (r) = diameter / 2 = 18.0 ft / 2 = 9.0 ft
Depth (h) = 3.75 ft

Volume of the pool (V) = π * r^2 * h = 3.14159 * (9.0 ft)^2 * 3.75 ft ≈ 954.92 cubic feet

Next, we need to convert the volume of the pool from cubic feet to gallons since the rate at which water is moved by the pump is given in gallons per minute.

1 cubic foot is approximately equal to 7.48 gallons, so we can multiply the volume by this conversion factor to get the volume in gallons.

Volume in gallons ≈ 954.92 cubic feet * 7.48 gallons/cubic foot ≈ 7139.14 gallons

Finally, we divide the volume of water in the pool by the pump's rate to find out how many minutes it will take to drain the swimming pool.

Time to drain = Volume in gallons / Pump rate = 7139.14 gallons / 7.58 gallons/minute ≈ 941.53 minutes

Therefore, it will take approximately 941.53 minutes (or about 15.69 hours) to completely drain the swimming pool using the given pump.