A block of mass 4.69 kg is hanging from a rope. The tension in the rope is 33.8 N, pulling upward on the block. What is the magnitude and direction of the acceleration of the block?

Tension=weigh+ma

33.8=4.69(g+a) solve for a, upwards if +, if negative, downward)

To find the magnitude and direction of the acceleration of the block, we can use Newton's second law of motion, which states that the net force acting on an object is equal to the mass of the object multiplied by its acceleration.

In this case, the net force acting on the block is the tension in the rope, given as 33.8 N, and the mass of the block is 4.69 kg.

Using Newton's second law, we have:

Net force = Mass x Acceleration

33.8 N = 4.69 kg x Acceleration

Now, we can solve for the acceleration:

Acceleration = 33.8 N / 4.69 kg

Acceleration ≈ 7.22 m/s²

The magnitude of the acceleration is approximately 7.22 m/s². Since the tension in the rope is pulling upward, the direction of the acceleration is also upward.