1)At 1 p.m., Lin records an outside temperature of –14.8°F. At 3 p.m... she records the outside temperature and notices the temperature had increased by 22.6 degrees.
What was the temperature that she recorded at 3 p.m.? ( no multiple choice) *my answer is 7.8*
2) (x - 16) + 5 = -15
This is not multiple choice but my answer is -11
3) 5 = –(–z + 3)
–8 *my answer*
8
-2
2
4) The temperature at the summit of Mt. Mansfield dropped 17°F between 4 p.m. and 11 p.m. The temperature at 11 p.m. was –11°F. What was the temperature at 4 p.m.?
17 – t = –11 *my answer*
t – 17 = –11
11 – 17 = t
17 + 11 = t
Thanks I was kinda confused on one or two
Steve answered you last night.
http://www.jiskha.com/display.cgi?id=1410830327
1) To find the temperature that Lin recorded at 3 p.m., we can start with the temperature recorded at 1 p.m., which is -14.8°F. We know that the temperature increased by 22.6 degrees, so we can add this to the initial temperature:
-14.8°F + 22.6°F = 7.8°F
Therefore, the temperature that Lin recorded at 3 p.m. is 7.8°F.
2) To solve the equation (x - 16) + 5 = -15, we can start by simplifying the left side of the equation:
(x - 16) + 5 = -15
x - 16 + 5 = -15
Next, we can combine like terms on the left side:
x - 11 = -15
To isolate x, we can add 11 to both sides of the equation:
x - 11 + 11 = -15 + 11
x = -4
Therefore, the value of x is -4.
3) To solve the equation 5 = –(–z + 3), we can start by distributing the negative sign:
5 = -(-z) - 3
Next, we can simplify the equation further:
5 = z - 3
To isolate z, we can add 3 to both sides of the equation:
5 + 3 = z - 3 + 3
8 = z
Therefore, the value of z is 8.
4) To solve the equation 17 - t = -11, we can start by isolating t. To do this, we can add t to both sides of the equation:
17 - t + t = -11 + t
17 = -11 + t
Next, we can simplify the equation further:
17 = t - 11
To isolate t, we can add 11 to both sides of the equation:
17 + 11 = t - 11 + 11
28 = t
Therefore, the temperature at 4 p.m. was 28°F.