1)At 1 p.m., Lin records an outside temperature of –14.8°F. At 3 p.m... she records the outside temperature and notices the temperature had increased by 22.6 degrees.

Question

1)At 1 p.m., Lin records an outside temperature of –14.8°F. At 3 p.m... she records the outside temperature and notices the temperature had increased by 22.6 degrees.

What was the temperature that she recorded at 3 p.m.? ( no multiple choice) *confused on this question*

2) (x - 16) + 5 = -15
This is not multiple choice but my answer is -11

3) 5 = –(–z + 3)

–8 *my answer*

8
-2

2

4) The temperature at the summit of Mt. Mansfield dropped 17°F between 4 p.m. and 11 p.m. The temperature at 11 p.m. was –11°F. What was the temperature at 4 p.m.?

17 – t = –11 *my answer*

t – 17 = –11

11 – 17 = t

17 + 11 = t
Thanks I was kinda confused on one or two

Answer 1

#1

-14.8 + 22.6 = 7.8

#2
(x - 16) + 5 = -15
x-16+5 = -15
x-11 = -15
x = -4

#3
5 = –(–z + 3)
5 = z-3
8 = z

#4
t - 17 = -11
Your choice is the situation where the temperature started at 17° and then decreased by t°.

Answer 2

1) To solve this question, we need to add the increase in temperature (22.6 degrees) to the initial temperature (-14.8°F). Adding these two values together will give us the temperature recorded at 3 p.m.

So, -14.8°F + 22.6°F = 7.8°F

Therefore, the temperature recorded at 3 p.m. is 7.8°F.

2) To solve the equation (x - 16) + 5 = -15, we need to isolate the variable x.

First, simplify the equation by combining like terms:

x - 16 + 5 = -15

x - 11 = -15

Next, isolate x by performing inverse operations. In this case, we add 11 to both sides of the equation:

x - 11 + 11 = -15 + 11

x = -4

So, the value of x is -4.

3) To solve the equation 5 = –(–z + 3), we need to isolate the variable z.

First, simplify the equation by using the rules of operations. Since there is a negative sign in front of the parentheses, we can distribute it:

5 = -(-z) + 3

Next, simplify further:

5 = z + 3

To isolate z, we subtract 3 from both sides of the equation:

5 - 3 = z + 3 - 3

2 = z

So, the value of z is 2.

4) To find the temperature at 4 p.m., we need to subtract the temperature drop (-17°F) from the temperature at 11 p.m. (-11°F).

In the equation 17 - t = -11, where t represents the temperature at 4 p.m., we can isolate t by performing inverse operations.

First, add 17 to both sides of the equation:

17 - t + 17 = -11 + 17

17 + 17 = t - 11

34 = t - 11

Next, add 11 to both sides of the equation:

34 + 11 = t - 11 + 11

45 = t

So, the temperature at 4 p.m. was 45°F.