Okay, so! I figured out how to get the Point-slope form to the question I was given which led me to y+3 =-2(x+1), but, now I'm stick on finding the Slope Intercept form to get my answer. Can someone help me? Thanks!
slope intercept form is in the form
y=ax+b
If you start from the equation above, you would isolate (solve for) y in terms of x and the constants, then simplify the right-hand side to remove parentheses.
Isolate y means use algebraic operations to leave only y on the left-hand side.
For example, 2y+1=4x+3
=>
2y = 4x+3-1 (after subtracting 1 from each side)
2y = 4x+1
y=2x+1/2 (after dividing by 2 on each side)
and this is now in slope-intercept form. (2 is the slope, 1/2 is the y intercept if you plot this line in a graph).
@ MathMate,
Here is the original question; Write the equation of the line with slope -2 that passes through the point (-1, -3) in slope-intercept form. But I've tried to figure out how to do it and I'm literally stuck.
I think the easiest way is to use the point-slope form of the equation, since they gave you a point and a slope. Recall that the equation for a line through (h,k) with slope m is
y-k = m(x-h)
So, you have
y+3 = -2(x+1)
Now work with that:
y+3 = -2x-2
y = -2x-5
Of course! I'd be happy to help you find the slope-intercept form of the equation. The slope-intercept form is given by the equation y = mx + b, where m represents the slope and b represents the y-intercept.
To find the slope-intercept form from the point-slope form, y + 3 = -2(x + 1), you can start by distributing -2 to both terms inside the parentheses:
y + 3 = -2x - 2
Next, you can isolate y by subtracting 3 from both sides of the equation:
y = -2x - 2 - 3
Simplifying, you get:
y = -2x - 5
Thus, the slope-intercept form of the equation is y = -2x - 5. The slope, represented by m, is -2 and the y-intercept, represented by b, is -5.