If a soft-drink bottle whose volume is 1.70LL is completely filled with water and then frozen to -10∘C, what volume does the ice occupy?
What's the temperature of the water when the bottle is first filled. Let's say it is such that the density of the watrer is 1.0 g/mL. If the problem doesn't tell you it can't be solved exactly.
If density i8s 1.0 g/mL, then the mass of the water is 1,700 grams.
Look up the density of water at -10C, then volume = mass/density. You have mass and densityk solve for volume. It will be larger than 1.70L
To find the volume occupied by the ice, we need to consider the density difference between water and ice. When liquid water freezes, it expands and becomes solid ice. The density of ice is lower than the density of water, which means that the same mass of ice occupies a greater volume than water.
To determine the volume of ice, we need to know the density of water and ice. The density of water is approximately 1 gram per cubic centimeter (g/cm³), which is equivalent to 1 kilogram per liter (kg/L).
Given that the volume of the soft-drink bottle is 1.70 liters (1.70 L) and it is completely filled with water, the mass of the water can be calculated using its density.
Mass of water = volume of water x density of water
Mass of water = 1.70 L x 1 kg/L (since density of water is 1 kg/L)
Mass of water = 1.70 kg
Now, let's consider the freezing process. When water freezes, its volume expands by about 9%. Therefore, the volume occupied by the ice will be greater than the initial volume of water.
Volume of ice ≈ (Volume of water) x (1 + Expansion factor)
Expansion factor ≈ 9% = 0.09
Volume of ice ≈ 1.70 L x (1 + 0.09)
Volume of ice ≈ 1.70 L x 1.09
Volume of ice ≈ 1.85 L
Therefore, the volume of ice is approximately 1.85 liters (1.85 L).