A driver brings a car traveling at 22m/s to a full stop in 2 seconds. How fast does the car uniformly decelerate?
Acceleration = (final velocity - initial velocity)/ time
=(0 - 22 m/s ) / 2 s
= -11 m/s²
The negative sign indicates that it is a deceleration (slowing down).
Well, I must say, that car sure knows how to bring the fun to a screeching halt! Now, let's calculate the deceleration, shall we?
To find the deceleration, we can use the formula: deceleration = change in velocity / time taken.
The change in velocity is from 22 m/s to 0 m/s. So, the change in velocity is 22 m/s.
The time taken to come to a stop is 2 seconds.
Now, we can plug those numbers into the formula:
deceleration = 22 m/s / 2 s
So, using my trusty math skills, the car uniformly decelerates at 11 m/s^2.
Remember, it's always important to drive safely and not become the punchline of a traffic joke!
To calculate the uniform deceleration of the car, we can use the equation:
Acceleration (a) = (Final Velocity (v) - Initial Velocity (u)) / Time (t)
Given:
Initial Velocity (u) = 22 m/s
Final Velocity (v) = 0 m/s
Time (t) = 2 seconds
Using the formula, we can substitute the given values:
Acceleration (a) = (0 - 22) / 2
Simplifying the equation:
Acceleration (a) = -11 m/s²
Therefore, the car is uniformly decelerating at a rate of -11 m/s². The negative sign indicates that the car is decelerating.
To find the deceleration of the car, we can use the formula:
acceleration = (final velocity - initial velocity) / time
In this case, the initial velocity (u) is 22 m/s, the final velocity (v) is 0 m/s, and the time (t) is 2 seconds.
Substituting the values into the formula:
acceleration = (0 m/s - 22 m/s) / 2 s
Simplifying the equation gives us:
acceleration = -22 m/s / 2 s
The negative sign signifies deceleration. Dividing -22 m/s by 2 s, we get:
acceleration = -11 m/s²
Therefore, the car decelerates uniformly at a rate of 11 m/s².