Determine the rule when gradient =2,x intercept =3 .can. anyone please explain,cause I know y intercept =c,but I don't know x intercept,thanks
hits x axis at 3 so goes through (3,0)
y = 2 x + b
0 = 2 (3) + b
b - -6
y = 2 x - 6
To determine the rule of a linear equation when given the gradient and x-intercept, you can use the point-slope form of a linear equation. The point-slope form is given by:
y - y1 = m(x - x1)
Where:
m = gradient
(x1, y1) = coordinates of a point on the line
In this case, you are given the gradient as 2 and the x-intercept as 3. The x-intercept is the point where the line intersects the x-axis, meaning the y-coordinate is 0.
So, let's substitute the given values into the point-slope form to find the equation of the line:
y - 0 = 2(x - 3)
Simplifying further:
y = 2(x - 3)
y = 2x - 6
Therefore, the rule for the linear equation with a gradient of 2 and x-intercept of 3 is y = 2x - 6.
I hope this explanation helps! Let me know if you have any further questions.