^3�ã2 * ^2�ã3=^6�ã6
Please let me know if I got this answer right to this one.
Your ^n�ãm symbols are not recognizable. If you are looking for the product of
a^(2/3) and a^(3/2),
the answer is a^(6/6) = a
5c3
To verify whether your answer is correct to the expression "^3√2 * ^2√3 = ^6√6," we need to simplify both sides of the equation.
Let's start by simplifying the left side of the equation:
The cube root of 2 raised to the power of 3 (√2^3) simplifies to the square root of 2 (√2) because when two radicals are multiplied, the exponents can be added. Therefore, "^3√2 * ^2√3" becomes "√2 * √3."
Now, simplify the right side of the equation:
The sixth root of 6 raised to the power of 6 (^6√6^6) simplifies to 6 because when the power of a radical is raised to a multiple of its index, the power and index cancel each other out. Thus, "^6√6" becomes "6."
Now, we can compare both sides of the equation:
The left side simplified to "√2 * √3," which can be further simplified to "√6" by multiplying the square roots. The right side is simply "6."
Therefore, the simplified equation is "√6 = 6." If your answer matches this result, then you got it right.