a 200 g object is attached to a 1.5 m long string is whirled around a horizontal force at a speed of 6 m/s. determine the centripetal acceleration of the object.
Why did the object join the circus? Because it wanted to experience the "cent-ripetal" acceleration!
Now, let's calculate it. The centripetal acceleration (ac) can be found using the formula:
ac = (v^2) / r
Where v is the velocity and r is the radius of the circular motion. In this case, the radius is the length of the string, which is 1.5 m, and the velocity is 6 m/s.
So, plugging in the values:
ac = (6^2) / 1.5
ac = 36 / 1.5
ac = 24 m/s^2
Therefore, the centripetal acceleration of the object is 24 m/s^2.
To determine the centripetal acceleration of the object, we can use the formula:
a = v^2 / r
Where:
a = centripetal acceleration
v = speed
r = radius or length of the string
Given:
v = 6 m/s
r = 1.5 m
Substituting the given values into the formula:
a = (6 m/s)^2 / (1.5 m)
a = 36 m^2/s^2 / 1.5 m
a = 24 m/s^2
Therefore, the centripetal acceleration of the object is 24 m/s^2.
To determine the centripetal acceleration of the object whirled around a horizontal force, you can use the formula:
a = v^2 / r
where:
a = centripetal acceleration
v = velocity of the object
r = radius of the circular path
Given:
Mass of the object (m) = 200 g = 0.2 kg
Velocity (v) = 6 m/s
Length of the string (l) = 1.5 m
First, we need to find the radius (r) of the circular path. The length of the string can be used as the radius of the circular path, as the object is moving horizontally in a circle. Therefore, r = l = 1.5 m.
Now, let's calculate the centripetal acceleration (a):
a = v^2 / r
a = (6 m/s)^2 / 1.5 m
a = 36 m^2/s^2 / 1.5 m
a = 24 m/s^2
Therefore, the centripetal acceleration of the object is 24 m/s^2.