Describe how you would prepare 90 mL of a 5 mM NaCl solution from a 2 M NaCl stock solution.

Describe your actions–exactly what you would do –step-by-step–when preparing this solution. Also show
all calculations. Be sure all amounts include units of measurement.

To prepare 90 mL of a 5 mM NaCl solution from a 2 M NaCl stock solution, here are the step-by-step actions:

1. Determine the amount of NaCl stock solution needed to make the desired concentration. You can use the formula:

C1V1 = C2V2

Where:
C1 = Initial concentration of the stock solution (2 M)
V1 = Initial volume of the stock solution (unknown)
C2 = Final concentration of the desired solution (5 mM)
V2 = Final volume of the desired solution (90 mL)

Rearrange the formula to solve for V1:
V1 = (C2 x V2) / C1

Plugging in the values:
V1 = (5 mM x 90 mL) / 2 M
V1 = 225 mM mL / M
V1 = 0.225 L or 225 mL

Therefore, you will need 225 mL of the 2 M NaCl stock solution.

2. Measure out 225 mL of the 2 M NaCl stock solution using a graduated cylinder or a pipette.

3. Dilute the stock solution with distilled water to achieve the desired volume. In this case, you want to make a 90 mL solution.

4. Pour the 225 mL of the stock solution into a 250 mL beaker.

5. Add distilled water slowly and carefully to the beaker while continuously stirring the solution to achieve a final volume of 90 mL.

6. Once the desired volume is reached, transfer the solution to a 100 mL volumetric flask to accurately measure the 90 mL volume.

7. Finally, label the volumetric flask clearly with the concentration, date, and any other necessary information.

This step-by-step process will result in preparing 90 mL of a 5 mM NaCl solution from a 2 M NaCl stock solution.

To prepare 90 mL of a 5 mM NaCl solution from a 2 M NaCl stock solution, here are the step-by-step actions and calculations:

1. Determine the volume and concentration of the stock solution needed.
- The volume needed for the final solution is 90 mL.
- The desired concentration is 5 mM.

2. Use the formula for calculating dilutions:
C1V1 = C2V2
where C1 and V1 represent the concentration and volume of the stock solution, and C2 and V2 are the concentration and volume of the final solution.

3. Rearrange the formula to solve for V1, the volume of the stock solution needed:
V1 = (C2 * V2) / C1

4. Substitute the given values into the formula:
V1 = (5 mM * 90 mL) / 2 M
Molarity (M) represents the concentration in moles per liter (mol/L), so we need to convert mL to L for both the stock solution and the final solution:
V1 = (5 mM * 0.09 L) / 2 M
Convert 90 mL to 0.09 L.

5. Calculate V1:
V1 = 0.45 mL

6. Measure 0.45 mL of the 2 M NaCl stock solution using a pipette or syringe.

7. Transfer the measured stock solution into a container or beaker.

8. Add distilled water to bring the total volume up to 90 mL. This will ensure the final concentration is 5 mM.

9. Mix the solution thoroughly to ensure uniform distribution.

You have now prepared 90 mL of a 5 mM NaCl solution from a 2 M NaCl stock solution.