A certain circuit breaker trips when the rms current is 50.0 A. What is the corresponding peak current?
divide by .707
which is 1/sqrt 2
To determine the corresponding peak current, we need to understand the relationship between root mean square (rms) current and peak current.
In an alternating current (AC) circuit, the rms current is the value of the steady current that would produce the same amount of heat in a resistor as the actual alternating current. It is a representation of the effective or average current in an AC circuit.
The relationship between rms current and peak current can be defined using the following formula:
I_peak = √2 * I_rms
Where:
I_peak represents the peak current
I_rms represents the rms current
Applying this formula to the given problem, we have:
I_rms = 50.0 A
Let's calculate the corresponding peak current:
I_peak = √2 * I_rms
I_peak = √2 * 50.0 A
I_peak ≈ 70.7 A
Therefore, the corresponding peak current is approximately 70.7 Amps.