3. Use the ratio of stoichiometric coefficients in the reaction above to determine how many moles of O2 will react with the H2 available.
Then, use molar mass to convert the moles of O2 into grams.
For the reaction 2H2 + 1O2 =2H2O, there are 8.08 grams of H2 available.
the ratio would be 2 h2 to 1 o2 but i don't know how to go from there how would u set it up?
there would be 32 g per mole for the mass of oxygen do u multiply 2 times 32?
mols H2 = grams/molar mass = 8.08/2 = 4.04. (I rounded for the molar mass H2; you may want to do it more accurately.)
Convert mols H2 to mols O2 using the coefficients in the balanced equation.
4.04 mols H2 x (1 mol O2/2 mols H2) = 4.04 x 1/2 = 2.02 mols O2 needed to react with 8.08 g H2.
Then g O2 = mols O2 x molar mass O2 = 2.02 mol x 32 g/mol = ?
2. Use the ratio of stoichiometric coefficients in the reaction above to determine how many moles of H2O can be produced from the H2 available.
Then, use molar mass to convert the moles of H2O into grams.
For the reaction 2H2 + 1O2 à 2H2O, there are 8.08 grams of H2 available.
I got the answer 324.36 grams would that be correct
To determine how many moles of O2 will react with the available H2, you need to use the stoichiometric ratio given in the chemical equation. In this case, the ratio is 2 moles of H2 to 1 mole of O2.
Since you have 8.08 grams of H2 available, you first need to convert this mass into moles. To do this, you divide the mass of H2 by its molar mass, which is 2.016 grams/mol.
moles of H2 = 8.08 g / 2.016 g/mol = 4 moles
Now that you know you have 4 moles of H2, you can use the stoichiometric ratio to determine the number of moles of O2 that will react. Since the ratio is 2 moles of H2 to 1 mole of O2, you can set up a proportion:
2 moles H2 / 1 mole O2 = 4 moles H2 / x moles O2
Cross-multiplying, you get:
2x = 4
x = 4 / 2
x = 2 moles
Therefore, 2 moles of O2 will react with the available H2.
To convert the moles of O2 into grams, you can use its molar mass, which is 32.00 grams/mol. Multiply the number of moles by the molar mass to get the mass of O2:
mass of O2 = 2 moles * 32.00 g/mol = 64 grams
So, 2 moles of O2 will react with the available H2, resulting in 64 grams of O2 consumed.