The length of a rectangle is 3 feet less than twice the width of the rectangle. If the perimeter of the rectangle is 144 feet, what is the length? am looking for the length, not the width. Thanks

I assume someone worked the problem for you and gave you instructions for the width. But if you know the width, use the equations to substitute and solve for the length. It can't be that bad. L is 2*w-3

To find the length of the rectangle, let's denote the width as 'w' and the length as 'l'. We are told that the length is 3 feet less than twice the width, so we can represent this as:

l = 2w - 3

We are also given that the perimeter of the rectangle is 144 feet. The perimeter of a rectangle is calculated by adding up the lengths of all its sides, which in this case is:

Perimeter = 2w + 2l

Substituting the value of l from the first equation, we have:

144 = 2w + 2(2w - 3)

Now, we can simplify and solve for 'w':

144 = 2w + 4w - 6
144 = 6w - 6
150 = 6w
w = 25

Now that we know the width is 25 feet, we can substitute this value back into the first equation to find the length:

l = 2(25) - 3
l = 50 - 3
l = 47

Therefore, the length of the rectangle is 47 feet.