A 5 oz carrot is burned in a calorimeter containing 10.0 lb of water. The water heats up from 20.5 oC to 22.8 oC. How many Calories are in the 5 oz carrot? Round to correct sig. fig.
1 Cal = 1000 cal.
Convert 5 oz to grams. There are 28.4 g in an oz. Convert 10.0 lb H2O to grams. There are 453.6 g in a lb.
q = mass H2O x specific heat H2O x (Tfinal-Tinitial)
You know Tf and Ti as well as mass H2O and specific heat H2O = 1 cal/g.
When q is calculated the unit will be calories. Convert that to Calories (actually that's kcal) by calories/1000 = kcal = Cal.
I forgot to add the weight of the 10.0 lbs of H2O. I got it, Thanks
To find the number of calories in the 5 oz carrot, we can use the equation:
Q = m * c * ΔT
Where:
Q is the amount of heat transferred (in calories)
m is the mass of the substance (in grams)
c is the specific heat capacity of the substance (in cal/g°C)
ΔT is the change in temperature (in °C)
First, let's convert the mass of the carrot from ounces to grams:
1 oz = 28.35 grams
So, 5 oz = 5 * 28.35 = 141.75 grams
Next, we need to convert the change in temperature from Fahrenheit to Celsius:
ΔT = 22.8 oC - 20.5 oC = 2.3 oC
Now, we need to determine the specific heat capacity of water. The specific heat capacity of water is approximately 1 cal/g°C.
Now we can plug all the values into the equation and solve for Q:
Q = 141.75 g * 1 cal/g°C * 2.3 oC
Q ≈ 326.1225 cal
Since 1 Cal = 1000 cal, we can convert the value to Calories:
326.1225 cal ÷ 1000 = 0.3261225 Cal
Rounding to the correct significant figure, the number of Calories in the 5 oz carrot would be:
0.33 Cal