Question

Please solve these using the quadratic formula:

1. 3x^2-4(x-2)=0
2.a^2+2(a++5)=0
3.x^2-3(2x+3)=0

Thank you ^____^

Answer 1

Tell you what. I'll solve one, and you can try the others. Post your work if you get stuck.

x^2-3(2x+3)=0
x^2-6x-9 = 0

x = (6±√(36+36))/2 = (6±6√2)/2 = 3±3√2