We did not find any results for 'a ball is projected vertically up with an initial speed of 20m/sec and acceleration due to gravity is 10m/s^2then how long will it take for the ball to reach a point 10m above the point of projection second line'
x = Xi + Vi t + .5 a t^2
10 = 20 t - 5 t^2
solve for t or just use
average speed up = 5 m/s
so time = distance/speed = 10/5 = 5