A car makes a 257 km trip at an average speed of 40 km/h. A second car starting 1 h later arrives at their mutual destination at the same time. What was the average speed of the second car for the period that it was in motion?

a=40
d=257 km
I don't know where to start or go from from here

To solve this problem, we can use the formula: average speed = total distance / total time.

First, let's find the total time it took for the first car to complete the trip. We know that the distance traveled by the first car is 257 km and its average speed is 40 km/h. Using the formula, we can calculate the total time for the first car:

Total time = distance / speed
Total time = 257 km / 40 km/h
Total time = 6.425 hours

Since the second car started 1 hour later, we can subtract 1 hour from the total time to find the time it took for the second car to complete the trip:

Time for the second car = Total time - 1 hour
Time for the second car = 6.425 hours - 1 hour
Time for the second car = 5.425 hours

Now, let's find the average speed of the second car during the time it was in motion. We know that the distance traveled by both cars is the same (257 km), and we have the time (5.425 hours) for the second car. Using the formula, we can calculate the average speed of the second car:

Average speed of the second car = total distance / total time
Average speed of the second car = 257 km / 5.425 hours
Average speed of the second car ≈ 47.4 km/h

So, the average speed of the second car for the period that it was in motion is approximately 47.4 km/h.