The length of a rectangle is 3 feet less than twice the width of the rectangle. If the perimeter of the rectangle is 144 feet, find the width and the length
2(w + 2w-3) = 144
The length of the rectangle is 3 less than twice the width.if the area is 9 square ft,the length and width of the rectangle
To find the width and length of the rectangle, we can use the given information about the relationship between the length and width, as well as the perimeter.
Let's start by assigning variables to the width and length of the rectangle. Let's say the width is "w" and the length is "l".
According to the problem, the length of the rectangle is 3 feet less than twice the width. This can be expressed as:
l = 2w - 3
The perimeter of a rectangle is given by the formula:
perimeter = 2(length + width)
Since the perimeter is given as 144 feet, we can write:
144 = 2(l + w)
Now, substitute the expression for the length (l) in terms of the width (w):
144 = 2((2w - 3) + w)
Simplify the equation:
144 = 2(3w - 3)
Divide both sides of the equation by 2:
72 = 3w - 3
Add 3 to both sides:
75 = 3w
Divide both sides by 3:
w = 25
Now that we have the width, we can substitute it back into the expression for the length:
l = 2w - 3
l = 2(25) - 3
l = 47
Therefore, the width of the rectangle is 25 feet and the length is 47 feet.