# physics

A kangaroo jumps straight up to a vertical height of 1.19m, how long was it in the air before returning on earth

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1. h = 0.5g*t^2 = 1.19 m.
4.9t^2 = 1.19
t^2 = 0.243
Tf = 0.493 s. = Fall time.

Tr = Tf = 0.493 s. = Rise time.

Tr+Tf = 0.493 + 0.493 = 0.986 s. = Time
in air.

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posted by Henry
2. why did you multiply it by 2

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posted by Michael

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