A ball player catches a ball 3.70s after throwing it vertically upward, what speed did he threw it
Tr = 3.70s/2 = 3.85 s. = Rise time.
Tr = -Vo/g = 3.85 s.
-Vo/-9.8 = 3.85
-Vo = -37.73
Vo = 37.73 m/s.
To find the speed at which the ball was thrown vertically upward, we can use the equation for vertical motion:
v = u + at
Where:
v = final velocity (0 m/s, since the ball comes to a stop at the highest point)
u = initial velocity (the speed at which the ball was thrown)
a = acceleration due to gravity (-9.8 m/s^2)
t = time taken to reach the maximum height (3.70 seconds)
Since the final velocity is zero when the ball reaches the highest point, we can rearrange the equation as:
0 = u - 9.8 * 3.70
Solving for u (initial velocity):
u = 9.8 * 3.70
u ≈ 36.26 m/s
Therefore, the ball was thrown vertically upward with a speed of approximately 36.26 m/s.