physics

What horizontal force is needed to push a hospital bed of mass 120 kg at a constant speed up a smooth sloping plane inclined at an angle of 37 degrees above the ground?

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asked by Lovely
  1. m*g = 120kg * 9.8N/kg = 1176 N. = Wt. of
    the bed.

    Fp = 1176*sin37 = 707.73 N. = Force
    parallel to the incline.

    Fn = 1176*cos37 = 939.20 N. = Normal =
    Force perpendicular to the incline.

    !@#$%^&-Fp = m*a
    !@#$%^&-707.73 = m*0 = 0
    !@#$%^& = 707.73 N. = Force applied parallel
    to the incline.

    Fx = !@#$%^&*cos A = 707.73*cos37 = 565 N.
    = Hor. force applied.

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    posted by Henry

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