physics

Runner A is initially 5.3 km west of a flagpole and is running with a constant velocity of 8.4 km/h due east. Runner B is initially 4.5 km east of the flagpole and is running with a constant velocity of 7.1 km/h due west. How far are the runners from the flagpole when their paths cross? Answer in units of km

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asked by belida
  1. Va*t + Vb*t = Da + Db.
    8.4t + 7.1t = 5.3 + 4.5
    15.5t = 9.8
    t = 0.63226 h = Time at which their paths cross.

    d = 4.5 - 7.1*0.63226 = 4.5 - 4.489 =
    0.01097 km = 11 m. East of flagpole.

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    posted by Henry

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