the sum of three consecutive odd integers is 435. What is the largest of the three integers??how do I solve this problem?? Please help
To solve this problem, we need to utilize the information given: the sum of three consecutive odd integers is 435.
Let's assume the first odd integer as x. Since the integers are consecutive odd numbers, the second odd integer will be x + 2, and the third odd integer will be x + 4.
To find the sum of these three consecutive odd integers, we add them together:
x + (x + 2) + (x + 4) = 435
Now, we combine like terms:
3x + 6 = 435
Next, we isolate the variable x by subtracting 6 from both sides:
3x = 429
Finally, divide both sides by 3:
x = 429 / 3
x = 143
Therefore, the first odd integer is 143.
To find the largest of the three integers, we add 4 to the first odd integer:
143 + 4 = 147
So, the largest of the three consecutive odd integers is 147.
Here's a start:
435/3 = ?
The sum of three consecutive odd integers is 435 Find the three integers.
odd numbers differ be 2
let the first of the odd numbers be x
then the next two odds are x+2, and x+4
x + x+2 + x+4 = 435
3x = 429
x = 143
so the largest is x+4 = 143+4 = 147