chemistry

what is the mass of oxygen in a 5.6 g sample of Al(NO3)3.

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asked by taylor
  1. How many mols Al(NO3)2 do you have?
    That's 5.6g/molar mass Al(NO3)3 = ?
    Then there are 9 mols O (not O2) for every 1 mol Al(NO3)3; therefore, mols Al(NO3)3 x 9 = mols O (not O2).
    Finally mols O x 16 = grams O.

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    posted by DrBob222

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