a rolling ball moves x1 = 8.0 cm to x2 = -4.3 cm during a time interval t1= 3.5 to t2- 6.9, what is the average velocity over this time interval
Vavg = (X2-X1)/(t2-t1)
Vavg = (-4.3-8.0)/(-6.9-3.5) =
-25
To find the average velocity over the given time interval, you can use the formula:
Average velocity = (change in position) / (change in time)
First, let's calculate the change in position:
Change in position = x2 - x1
= -4.3 cm - 8.0 cm
= -12.3 cm
Next, let's calculate the change in time:
Change in time = t2 - t1
= 6.9 - 3.5
= 3.4
Now, let's calculate the average velocity:
Average velocity = (change in position) / (change in time)
= -12.3 cm / 3.4
≈ -3.62 cm/s
Therefore, the average velocity over this time interval is approximately -3.62 cm/s.
To calculate the average velocity of the rolling ball, you need to use the formula:
average velocity = (change in position) / (change in time)
The change in position (Δx) is calculated by subtracting the initial position (x1) from the final position (x2):
Δx = x2 - x1
The change in time (Δt) is calculated by subtracting the initial time (t1) from the final time (t2):
Δt = t2 - t1
Now, let's calculate the values:
Δx = -4.3 cm - 8.0 cm
= -12.3 cm
Δt = 6.9 - 3.5
= 3.4
The average velocity can be calculated by dividing the change in position by the change in time:
average velocity = Δx / Δt
= -12.3 cm / 3.4
Finally, we can calculate the average velocity of the rolling ball:
average velocity ≈ -3.62 cm/s
So, the average velocity of the ball over the time interval from 3.5 to 6.9 seconds is approximately -3.62 cm/s. Note that the negative sign indicates the direction of motion.