A 1600n is supported by two cables of equal length two ends are fasted by two nail by place horizontal level at 8m part .find the tension each cables when the block6m below the horizontal level.
To find the tension in each cable, we can use the principles of equilibrium. When an object is in equilibrium, the sum of the vertical forces and the sum of the horizontal forces acting on it must be zero.
Let's assume the tension in each cable is T.
Vertical forces:
1) Weight of the block = 1600 N (acting downward)
2) Tension in each cable = T (upward force)
Since the block is 6m below the horizontal level, the vertical distance between the block and the horizontal level is 6m.
Using the equation for vertical forces:
Weight of the block - Tension = 0
1600 N - 2T = 0
1600 N = 2T
Now let's consider the horizontal forces:
The horizontal forces acting on the block are the tension in each cable. Since the horizontal level is 8m apart, the horizontal distance between the two cables is 8m.
Using the equation for horizontal forces:
Tension + Tension = 0 (as the forces are in opposite directions)
2T = 0
T = 0
Now, substituting the value of T into the equation we found earlier, we can solve for T:
1600 N = 2T
1600 N = 2 * 0
1600 N = 0
Since the equation 1600N = 0 does not hold, it means there is no solution to this problem. This indicates that the situation described in the question cannot exist in reality. The tension in each cable cannot be determined without any additional information or assumptions.