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Given: ________, – 243, – 226, – 209, – 192, – 175, … The 67th term of the sequence is __________. The series of the first 27 terms of the sequence is __________.
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1. 77 is what percent of 192? A. x/100=77/192;4.01%**** B. x/100=77/192;40.1% C. x/77=100/192;77.3% D. x/100=192/77;249.4% 2.Of the 80 eigthgraders, 32 are going on the class retreat. What percnt of the eigth grade going on the
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Find X 27^4x2=243^3x+6 Please explain how to do it. Thanks 27^(4x2)=243^(3x+6) Notice that 27 and 243 are both multiples of 3 Changing them.. (3^4)^(4x2)=(3^6)^(3x+6) 3^4(4x2)= 3^6(3x+6) taking the log base 3 of each side.
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77 is what percent of 192? A. x/100= 77/192;4.01% B. x/100=77/192; 40.1% C. x/77= 100/192; 77.3% D. x/100= 192/77; 249.4% My answer is B. Please help and check my answer if I am wrong please correct me thank you.
asked by Gurl nerd on December 5, 2017 
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Find X 27^4x2=243^3x=6 Please Explain Thanks Is this a repeat of the problem you posted earlier? If so, it should be 274x2 = 2433x+6 You might try it the hard way. (4x2)*log 27 = (3x+6)*log (243) Solve for x. I get 12. Post
asked by K on November 28, 2006