I just wanted to double check that I am correct. Answer is in Interval Notation.
1. Solve: |x|<7
Work: -7>x<7
Answer: (-7,7)
2. Solve: |x|>_ 7
Work: -7<_ x >_ 7
Answer: ( - infinity sign, -7] U [7, infinity sign)
1. correct in interval notation
in standard notation: -7 < x < 7
- when written in this notation, the word "and" is used
2.
|x| ≥ 7
x ≥ 7 OR -x ≥ 7
x ≥ 7 or x ≤ -7
so yes, you are correct
( I don't like the way you showed your steps in "work" )