A cart on a linear track has a uniform acceleration of 0.172 m/s^2. What is the velocity of the cart 4.00 s after it is released from rest?

What is the answer

To find the velocity of the cart 4.00 seconds after it is released from rest, we can use the equation for uniformly accelerated linear motion:

v = u + at

Where:
v = final velocity
u = initial velocity (in this case, the cart is released from rest, so u = 0)
a = acceleration
t = time

Given:
a = 0.172 m/s^2
t = 4.00 s

Substituting the given values into the equation, we get:

v = 0 + (0.172 m/s^2)(4.00 s)

v = 0 + (0.688 m/s)

v = 0.688 m/s

Therefore, the velocity of the cart 4.00 s after it is released from rest is 0.688 m/s.

To find the velocity of the cart after 4.00 seconds, we can use the equation of motion for uniformly accelerated motion:

v = u + at

Where:
v = final velocity
u = initial velocity (in this case, the cart is released from rest, so u = 0)
a = acceleration
t = time

Plugging in the given values:
a = 0.172 m/s^2
t = 4.00 s

v = 0 + (0.172 m/s^2)(4.00 s)
v = 0 + 0.688 m/s
v = 0.688 m/s

Therefore, the velocity of the cart 4.00 s after it is released from rest is 0.688 m/s.

V = a*t