Physics

You have three balls, one is thrown upward at 30m/s, on is dropped, and one is thrown toward the ground at 20m/s. what is the acceleration of the dropped ball?
Vf=0m/s + (-10m/s^2)(1)
=0m/s -10m?s^2
= -10m/s

a= -10m/s * 0 /1
= 0
am i on the right track.....?
please help

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  1. a = g = 9.8 m/s^2.

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    posted by Henry

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