physic

a car travels east at 89 km/h for 1 hour.it then travels 26 east of north at 141 km/h for another 1 hour.

a)what is the average speed for the trip?
b)what is the average velocity for the trip?

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asked by siti
  1. a. d = 89 + 141km[64o[]CCW.
    d = 89 + 141*Cos64 + i141*sin64
    d = 89 + 61.8 + 126.7i = 150.8 + 126.7i
    = 196.9km[40o]

    Speed = d/t = 196.9km/2h = 98.4km/h.

    b. V = 196.9km[40o]/2h = 98.4km/h[40o].
    = 98.4km/h[50o] E of N.

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    posted by Henry

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