Suppose you have two 100-{\rm mL} graduated cylinders. In each cylinder there is 58.5mL of water. You also have two cubes: One is lead, and the other is aluminum. Each cube measures 2.0cm on each side.
After you carefully lower each cube into the water of its own cylinder, what will the new water level be in each of the cylinders? Assume that cubes are totally emerged in the water.
volume of water = 58.5 mL
volume cubes = 2.0 x 2.0 x 2.0 = 8 cc = 8 mL.
new volume in BOTH graduated cylinders is
58.5 + 8 = ?
No, I didn't err. Both Pb and Al have the same volume so the water levels will be the same when both are submerged.
Ethyl alcohol has a specific gravity of 0.79 what is the volume in quarts of 1.35 kg of alcohol?
To determine the new water level in each of the cylinders after the cubes are added, we need to consider the displacement of water caused by the cubes.
The volume of each cube can be calculated using the formula for the volume of a cube: V = side^3. Given that each side of the cube measures 2.0 cm, we can calculate the volume of each cube as follows:
Volume of lead cube = (2.0 cm)^3 = 8.0 cm^3
Volume of aluminum cube = (2.0 cm)^3 = 8.0 cm^3
Since each 1 cm^3 is equivalent to 1 mL, we can conclude that both the lead cube and the aluminum cube displace 8.0 mL of water when fully submerged.
In each of the cylinders, there is initially 58.5 mL of water. When the cube is added to each cylinder, the water level will rise by the amount of water displaced by the cube.
For the lead cube, the new water level in the cylinder would be 58.5 mL (initial water volume) + 8.0 mL (volume of the lead cube) = 66.5 mL.
For the aluminum cube, the new water level in the cylinder would also be 58.5 mL (initial water volume) + 8.0 mL (volume of the aluminum cube) = 66.5 mL.
Therefore, the new water level in each of the cylinders after adding the respective cubes will be 66.5 mL.