Calculus-Math

f(x) = (1/2)x ln(x^6) (−1, 0)
(a) Find an equation of the tangent line to the graph of f at the given point.

y=

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  1. f'=1/2 ln(x^6) + 1/2 x/x^6 * 6x^5
    put in x=-1, f' is the slope of the graph at x=-1,0

    tangent line:
    y=mx + b
    0=f'(-1,0) * -1 + b solve for b
    then
    y=f'(-1,0) x + b is the equation

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