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The rectangle box with square base is open at the top. The maximum volume of the box made from 1200 m2 tin,in m3 is:

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  1. area = 1200 = x^2 + 4 x h
    so
    h = (1200-x^2)/4x

    v = x^2h
    v = (1/4)x(1200-x^2)
    dv/dx 0 at min or max
    0 = x(-2x) + 1200 - x^2

    3 x^2 = 1200
    x^2 = 400
    x = 20

    h = 400/80 = 5

    v = 400 *5 = 2000

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    posted by Damon
  2. answer will be 4000 . calculation mistake.

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