AP CAlc. AB

limit x->0 (3k+k(x^2) sin(1/x)), if k is a positive constant

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asked by Lily
  1. since |sinx| <= 1,

    x^2 sin(1/x) -> 0 as x->0

    So, all that's left is 3k.
    Doesn't really matter whether k is positive or not.

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    posted by Steve
  2. Thank you so much Steve!!!

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    posted by Lily

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