# AP CAlc. AB

limit x->0 (3k+k(x^2) sin(1/x)), if k is a positive constant

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asked by Lily
1. since |sinx| <= 1,

x^2 sin(1/x) -> 0 as x->0

So, all that's left is 3k.
Doesn't really matter whether k is positive or not.

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posted by Steve
2. Thank you so much Steve!!!

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posted by Lily

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