A simple lever is used to lift a heavy load. When a 60-N force pushes one end of the lever down 1.2 m, the load rises 0.2 m. Show what the weight of the load is 360N.

F2*d2 = F1*d1

F2*0.2 = 60 * 1.2
0.2F2 = 72
F2 = 360 N.

Well, it seems like this lever needs to hit the gym! Let's start by using the formula for a lever: F1d1 = F2d2, where F1 is the effort force, d1 is the distance from the effort force to the fulcrum, F2 is the load force, and d2 is the distance from the load force to the fulcrum.

We have F1 = 60 N, d1 = 1.2 m, F2 = unknown load force, and d2 = 0.2 m. Plugging in these values, we get:

60 N x 1.2 m = F2 x 0.2 m

Simplifying the equation:

72 N·m = 0.2F2

Now, let's solve for F2:

F2 = 72 N·m / 0.2 m

F2 ≈ 360 N

So, it appears the weight of the load is 360 N. That's quite a heavy load! I hope the lever doesn't break into a lever-rible situation!

To find the weight of the load, we can use the principle of moments.

The principle of moments states that the sum of the clockwise moments about any point is equal to the sum of the counterclockwise moments about the same point. In this case, we can consider the pivot of the lever as the point.

Let's assume the distance between the pivot point and the point where the force is applied is 'a', and the distance between the pivot point and the point where the load is lifted is 'b'.

According to the principle of moments, the clockwise moment caused by the force applied on one end of the lever is equal to the counterclockwise moment caused by the weight of the load.

The clockwise moment (M1) is given by:
M1 = Force * b

The counterclockwise moment (M2) is given by:
M2 = Weight * a

Since the lever is in equilibrium (no net rotation), M1 must be equal to M2:
M1 = M2

Therefore,
Force * b = Weight * a

We are given that the force (F) is 60 N, the distance (b) is 1.2 m, and the distance (a) is 0.2 m.

Plugging these values into the equation, we can solve for the weight (W):
60 N * 1.2 m = W * 0.2 m

72 N m = 0.2 W

Dividing both sides of the equation by 0.2:
360 N = W

Therefore, the weight of the load is 360 N.

To solve this problem, we can use the principle of the lever, which states that the effort force multiplied by the effort distance is equal to the load force multiplied by the load distance. In this case, we know the effort force (60 N), the effort distance (1.2 m), and the load distance (0.2 m), and we need to find the load force.

First, let's write the equation based on the principle of the lever:

Effort force * Effort distance = Load force * Load distance

Substituting the known values:

60 N * 1.2 m = Load force * 0.2 m

Now, let's solve for the load force:

Load force = (60 N * 1.2 m) / 0.2 m = 360 N

Therefore, the weight of the load is 360 N.