An all girl college began enrolling boys in 2005. By 2012 the ratio of boys to girls was 3 to 7. If there are 200 more girls than boys how many boys are there?

3/10 are boys

7/10 are girls

total boys = x
total girls = x+200
total students = 2x+200

(3/10)(2x+200) = x

6 x + 600 = 10 x

4 x = 600

x = 150

150 more boys enrolled that year.

if there are boys to girls a ratio of 7:3 and 200 more girls enrolled how many boys will be there.

To find the number of boys in 2012, we can start by representing the number of boys and girls in 2005. Let's assume that in 2005, there were x girls in the college and no boys.

Since the college began enrolling boys in 2005, the number of boys would still be 0 in that year.

Given that the ratio of boys to girls in 2012 is 3:7, we can assign values to these ratios as 3x and 7x, respectively.

According to the problem, there were 200 more girls than boys in 2012. So we can set up the equation:

7x - 3x = 200

Simplifying this equation, we get:

4x = 200

Dividing both sides of the equation by 4, we find that:

x = 50

Therefore, the number of boys in 2012 would be 3x = 3 * 50 = 150 boys.

Thus, there are 150 boys in the college in 2012.