physics

a fire hose hold near the ground shoots water at speed of 6.8 m/s at what angle(s) should the nozzle point in order that the water land 2 dm away why are there two diffent angles?

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  1. Do you mean 2 meters away? If so,

    Dx = Vo^2*sin(2A)/g = 2 m.
    6.8^2*sin(2A)/9.8 = 2.
    46.24*sin(2A) = 19.6
    sin(2A) = 0.42388
    2A = 25.1o
    A = 12.54o

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    posted by Henry

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