# algebra

2x^=5-2x find the real solution using the quadratic formula

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1. first rearrange the terms so you have

2x^2 + 2x - 5 = 0
Now just plug in the formula, where
a = 2
b = 2
c = -5

x = (-2±√(2^2 + 4*2*5))/(2*2)
= (-2±√44)/4
= (-1±√11)/2

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posted by Steve

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