algebra

2x^=5-2x find the real solution using the quadratic formula

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asked by sue
  1. first rearrange the terms so you have

    2x^2 + 2x - 5 = 0
    Now just plug in the formula, where
    a = 2
    b = 2
    c = -5

    x = (-2±√(2^2 + 4*2*5))/(2*2)
    = (-2±√44)/4
    = (-1±√11)/2

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    posted by Steve

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