find the distance across the corners of square nut is 7.9mm on a side
7.9 * sqrt 2
To find the distance across the corners of a square nut, we can use the Pythagorean theorem. The Pythagorean theorem states that in a right triangle, the square of the length of the hypotenuse (the side opposite the right angle) is equal to the sum of the squares of the other two sides.
In the case of a square nut, the two legs of the right triangle are the sides of the square, and the hypotenuse is the distance across the corners of the nut.
Given that the side of the square nut is 7.9 mm, we can calculate the distance across the corners using the Pythagorean theorem.
Let's label one side of the square nut as 's' (which is 7.9 mm in this case). The diagonal across the square nut can be represented as 'd'.
Using the Pythagorean theorem, we have:
d² = s² + s²
d² = 2s²
Now, substitute the value of 's':
d² = 2 * (7.9 mm)²
d² = 2 * 62.41 mm²
d² = 124.82 mm²
To get the distance across the corners, we take the square root of both sides:
d = √(124.82 mm²)
d ≈ 11.17 mm
Therefore, the distance across the corners of the square nut is approximately 11.17 mm.