a chemical reaction released 50.0kJ of energy as it heated a sample of water from 17.0 degrees celsius to 75.0 degrees Celsius, what mass of water was heated? I have no clue as to how to do this! can anyone help?
E=mc*temp change 50,000=M*4200*(75-17) M=50,000/4200*58 M=0.205Kg
Sure! I can help you with that. To solve this problem, we can use the equation:
q = mcΔT
Where:
q is the heat energy in joules
m is the mass of the water in grams
c is the specific heat capacity of water, which is approximately 4.18 J/g°C
ΔT is the change in temperature in Celsius
First, let's convert the given energy of 50.0 kJ to joules. Since 1 kJ is equal to 1000 J, we have:
50.0 kJ * 1000 J/kJ = 50,000 J
Next, we need to calculate the change in temperature, ΔT. It can be found by subtracting the initial temperature (17.0°C) from the final temperature (75.0°C):
ΔT = 75.0°C - 17.0°C = 58.0°C
Now, we can rearrange the equation and solve for mass (m):
q = mcΔT
m = q / (cΔT)
Substituting the known values:
m = 50,000 J / (4.18 J/g°C * 58.0°C)
Now, let's calculate the mass:
m ≈ 212.59 g
Therefore, the mass of the water that was heated is approximately 212.59 grams.