-Use upward as positive and 10.0 m/s2 for the magnitude of g.
-Let us say that you toss an object upwards at 5.0 from a height of 17.0 m.
1.)What is in m/s2 the acceleration of the object the moment it reaches the highest position?
2.)What is in m/s2 the acceleration of the object while it is moving upwards?
To find the acceleration of the object at different moments, we need to consider the concept of acceleration due to gravity (g).
1.) The acceleration of the object at the highest position can be found by assuming the object has reached its maximum height and is momentarily at rest before falling downwards. At this point, the acceleration due to gravity will act in the opposite direction (downwards) and will be equal to the magnitude of g. Therefore, the acceleration of the object at the highest position is 10.0 m/s^2 (downwards).
2.) The acceleration of the object while it is moving upwards can be found by considering the direction of motion and the acceleration due to gravity. Since the object is moving upwards, we need to take the acceleration due to gravity in the opposite direction (upwards). Therefore, the acceleration of the object while it is moving upwards is -10.0 m/s^2. The negative sign indicates that the acceleration is in the opposite direction to the positive direction defined earlier.
To summarize:
1.) The acceleration of the object at the highest position is 10.0 m/s^2 (downwards).
2.) The acceleration of the object while it is moving upwards is -10.0 m/s^2.