one number is three less than six times second number. their sum is 32. find the two numbers
second number --- x
first number = 6x-3
x + 6x-3 = 32
7x = 35
x = 5
one is 5 , the other is 27
What number is less than another if 6X a smaller number is added to five times the larger number the sum is 153 find the two numbers
Let's represent the first number as x and the second number as y.
According to the problem, the first number is three less than six times the second number:
x = 6y - 3 (equation 1)
The sum of the two numbers is 32:
x + y = 32 (equation 2)
Now we can solve the system of equations.
Substituting the value of x from equation 1 into equation 2:
(6y - 3) + y = 32
7y - 3 = 32
Adding 3 to both sides:
7y = 35
Dividing by 7:
y = 5
Substituting this value back into equation 2 to find x:
x + 5 = 32
x = 32 - 5
x = 27
Therefore, the two numbers are x = 27 and y = 5.
To find the two numbers, we can set up a system of equations based on the given information.
Let's assume the first number is represented by 'x' and the second number is represented by 'y'.
According to the first statement, "one number is three less than six times the second number," we can write the equation:
x = 6y - 3
According to the second statement, "their sum is 32," we can write the equation:
x + y = 32
Now we have a system of two equations:
1) x = 6y - 3
2) x + y = 32
To solve this system of equations, we can use the substitution method or the elimination method.
Let's use the substitution method to find the values of x and y:
From equation 1), we can isolate 'x' in terms of 'y':
x = 6y - 3
Next, substitute this expression for 'x' in equation 2):
(6y - 3) + y = 32
Now, simplify and solve for 'y':
7y - 3 = 32
7y = 32 + 3
7y = 35
y = 35/7
y = 5
Now that we have the value of 'y', we can substitute it back into equation 1) to find 'x':
x = 6(5) - 3
x = 30 - 3
x = 27
So, the two numbers are x = 27 and y = 5.