A car drives 55 km east in a time of 1.6 hours and then drives west some distance. However, the total distance traveled for the entire trip is 338 km and the total time taken for the entire trip is 2.6 hours. What is the average speed of the second part of the trip (when heading west) in km/hr?
distance east=55km
distance west=338-55= you do it.
avg speed going west= distance/time
= (338-55)/(2.6-1.6)
Your teacher is too easy.
To find the average speed of the second part of the trip (when heading west), we need to determine the distance traveled and the time it took during that part of the trip.
We already know that the total distance for the entire trip is 338 km. From this, we can subtract the distance traveled eastward during the first part of the trip to find the distance traveled westward during the second part of the trip.
Total distance traveled during the first part of the trip = 55 km (eastward)
Thus, the distance traveled during the second part of the trip is:
Distance traveled westward = Total distance - Distance traveled eastward
Distance traveled westward = 338 km - 55 km
Distance traveled westward = 283 km
Now, let's find the time taken during the second part of the trip. The total time taken for the entire trip is 2.6 hours, and we already know that the time taken during the first part of the trip was 1.6 hours.
Thus, the time taken during the second part of the trip is:
Time taken westward = Total time taken - Time taken eastward
Time taken westward = 2.6 hours - 1.6 hours
Time taken westward = 1 hour
Finally, we can calculate the average speed of the second part of the trip (when heading west):
Average speed = Distance traveled ÷ Time taken
Average speed = 283 km ÷ 1 hour
Average speed = 283 km/hr
Therefore, the average speed of the second part of the trip (when heading west) is 283 km/hr.