You have a stock solution that is 350g/L . You perform a 9-fold serial dilution four times. What concentrations will you have in each of your diluted tubes in g/L? (Separate your answers with a comma.)
To determine the concentrations in each diluted tube, we need to calculate the dilution factor at each step and then multiply it by the initial concentration.
In a 9-fold serial dilution, the dilution factor is 1/9 or 0.1111. To calculate the concentration in the first diluted tube, we multiply the initial concentration (350 g/L) by the dilution factor:
Concentration in the first diluted tube = 350 g/L * 0.1111 = 38.88 g/L
For each subsequent diluted tube, we repeat the same process. The dilution factor remains constant at 0.1111.
Concentration in the second diluted tube = Concentration in the first diluted tube * 0.1111 = 38.88 g/L * 0.1111 = 4.32 g/L
Concentration in the third diluted tube = Concentration in the second diluted tube * 0.1111 = 4.32 g/L * 0.1111 = 0.48 g/L
Concentration in the fourth diluted tube = Concentration in the third diluted tube * 0.1111 = 0.48 g/L * 0.1111 = 0.053 g/L
Therefore, the concentrations in each of the diluted tubes are:
38.88 g/L, 4.32 g/L, 0.48 g/L, 0.053 g/L